By Steven Karris

ISBN-10: 1934404179

ISBN-13: 9781934404171

This article is an creation to the elemental ideas of electric engineering and covers DC and AC circuit research and Transients. it's meant for all engineering majors and presumes wisdom of first yr differential and crucial calculus and physics. The final chapters comprise step by step methods for the suggestions of straightforward differential equations utilized in the derivation of the usual and forces responses. Appendices A, B, and C are introductions to MATLAB, Simulink, and SimPowerSystems respectively. Appendix D is a evaluation of advanced Numbers, and Appendix E is an creation to matrices and determinants. for additional info. please stopover at the Orchard courses web site

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**Additional resources for Circuit Analysis I with MATLAB Computing and Simulink/SimPowerSystems Modeling**

**Sample text**

We will derive the total response of a parallel RLC circuit which is excited by an AC source with the following example. 22, i L 0 = 2 A and v C 0 = 5 V . Compute and sketch v t for t 0 . 22. 6 Solution: This is the same circuit as the previous example where the DC source has been replaced by an AC source. The total response will consist of the natural response v n t which we already know from the previous example, and the forced response v f t which is the AC steadystate response, will be found by phasor analysis.

50) and the constants k 1 and k 2 will be evaluated from the initial conditions. 51) k1 + k2 = 5 The second equation that is needed for the computation of the values of k 1 and k 2 is found from dv dt dv dt the other initial condition, that is, i L 0 = 2 A . 55) Check with MATLAB: syms t % Define symbolic variable t. 17. 17. , and the maximum voltage is approximately 24 V . 55), set it equal to zero, and solve for t . 76 V A useful quantity, especially in electronic circuit analysis, is the settling time, denoted as t S , and it is defined as the time required for the voltage to drop to 1% of its maximum value.

Then, P = --------------------------- = 0 = ---------------------- where R' = R + 2 . Therefore, 2R' 1 12 3 1 12 12 2 -------------------= 4 , or 2R + 2 6 2 2 -----------= 4 , or R + 2 = 36 4 = 9 , or R + 2 = 3 and thus R = 1 . R + 2 At t = 0 the circuit is as shown below. 2 A 6 6 At t = 0 + the circuit is as shown below. 4 (3) t=0 Also, --------C- = ---C- and at t = 0 dv C --------dt t=0 iC 0 0 = ----------- = ---- = 0 (4) C C because at t = 0 the capacitor is an open circuit.

### Circuit Analysis I with MATLAB Computing and Simulink/SimPowerSystems Modeling by Steven Karris

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